Fix argument parsing bug

Things like `luma(1, key: "val")` didn't produce an error before because `args.finish()?` wasn't called. This changes `args: Args` to `args: &mut Args` to make it impossible for that to happen.

1 files changed, 13 insertions, 1 deletions

diff --git a/tests/typ/compiler/array.typ b/tests/typ/compiler/array.typ
index 4191d6ff..2ce47158 100644
--- a/tests/typ/compiler/array.typ
+++ b/tests/typ/compiler/array.typ
@@ -249,6 +249,10 @@
 #test((2, 1, 3, -10, -5, 8, 6, -7, 2).sorted(key: x => x * x), (1, 2, 2, 3, -5, 6, -7, 8, -10))
 
 ---
+// Error: 12-18 unexpected argument
+#().sorted(x => x)
+
+---
 // Test the `zip` method.
 #test(().zip(()), ())
 #test((1,).zip(()), ())
@@ -262,7 +266,7 @@
 #test((1,).zip((2,), (3,)), ((1, 2, 3),))
 #test((1, 2, 3).zip(), ((1,), (2,), (3,)))
 #test(array.zip(()), ())
-#test(array.zip(("a", "b")), (("a",), ("b",)))
+
 
 ---
 // Test the `enumerate` method.
@@ -290,6 +294,14 @@
 #test(("Hello", "World", "Hi", "There").dedup(key: x => x.at(0)), ("Hello", "World", "There"))
 
 ---
+// Error: 9-26 unexpected argument: val
+#().zip(val: "applicable")
+
+---
+// Error: 13-30 unexpected argument: val
+#().zip((), val: "applicable")
+
+---
 // Error: 32-37 cannot divide by zero
 #(1, 2, 0, 3).sorted(key: x => 5 / x)